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Consider the following carbocations
The relative stabilities of these carbocations are such that:-

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$d < b < c < a$

$b < d < c < a$

$d < b < a < c$

$b < d < a < c$

answer is A.

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Detailed Solution

Correct Answer: (A)
d<b<c<a

d = primary carbocation → least stable.

b = secondary carbocation → more stable than primary.

c = resonance-stabilized (allylic/benzylic) → more stable than secondary.

a = tertiary + resonance (maximum stabilization) → most stable.

So the stability order is d < b < c < a.

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