Consider the following cases of standard enthalpy of reaction ΔHr∘ in kJmol−1C2H6(g)+72O2(g)→2CO2(g)+3H2O(ℓ)ΔH1o=−1550C( graphite )+O2(g)→CO2(g)ΔH2o=−393.5H2(g)+12O2(g)→H2O(ℓ)ΔH3o=−286The magnitude of ΔHf C2H6(g)o is _____

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Consider the following cases of standard enthalpy of reaction $({ΔH}_{r}^{\circ} in {kJmol}^{- 1})$

$\begin{array}{l} C_{2} H_{6} (g) + \frac{7}{2} O_{2} (g) \to 2 {CO}_{2} (g) + 3 H_{2} O (ℓ) {ΔH}_{1}^{o} = - 1550 \\ C (graphite) + O_{2} (g) \to {CO}_{2} (g) {ΔH}_{2}^{o} = - 393.5 \\ H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (ℓ) {ΔH}_{3}^{o} = - 286 \end{array}$

The magnitude of ${ΔH}_{f C_{2} H_{6} (g)}^{o}$ is ______ kJ mol^–1 (Nearest integer).

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answer is 95.

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Detailed Solution

$\begin{array}{l} 2 C_{(graphite)} + 3 H_{2} (g) \to C_{2} H_{6} (g) {ΔH}_{f} = ? \\ C_{2} H_{6} (g) + \frac{7}{2} O_{2} (g) \to 2 {CO}_{2} (g) + 3 H_{2} O (l) \\ {ΔH}_{1} = - 1550 \\ C_{(graphite)} + O_{2} (g) \to {CO}_{2} (g) {ΔH}_{2} = - 393.5 \\ H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (/) {ΔH}_{3} = - 286 \\ {ΔH}_{f} = 2 {ΔH}_{2} + 3 {ΔH}_{3} - {ΔH}_{1} \\ = 95 kJ / mole. \end{array}$