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Consider the following changes:
a) Sublimation energy of $M = P$
b) Sublimation energy $+ I . E ._{1} + I . E ._{2} of M = q$
c) $I . E ._{1} of M = r$
d) $I . E ._{2} of M = s$
e) $I . E ._{1} + I . E ._{2} of M = t$
The enthalpy change for the reaction could be calculated from the energy value associated with:

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$(p) + (r) + (s)$

$(q) - (p) + (r)$

$(p) + (t)$

$(t) - (r)$

answer is D.

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Detailed Solution

$I . E ._{2} =$ amount of energy required to remove one electron from unipositive ion
(Reaction – 4) $= X_{g}^{+} \to X_{g}^{2 +} + e^{-}$
Or (Reaction -5 – Reaction -3)

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