Q.

Consider the following changes:
a) Sublimation energy of M=P
b) Sublimation energy +I.E.1+I.E.2ofM=q
c) I.E.1ofM=r 
d) I.E.2ofM=s 
e) I.E.1+I.E.2ofM=t
The enthalpy change for the reaction  could be calculated from the energy value associated with:
 

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a

(p)+(r)+(s)

b

(q)(p)+(r)

c

(p)+(t)

d

(t)(r)

answer is D.

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Detailed Solution

I.E.2= amount of energy required to remove one electron from unipositive ion
 (Reaction – 4) =Xg+Xg2++e
 Or (Reaction -5 – Reaction -3)
 

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