Consider the following complex [Co(NH₃)₅CO₃]ClO₄.The coordination number, oxidation number, number of d-electrons and number of unpaired d-electrons, respectively, on the metal are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

7, 1, 6, 4

7, 2, 7, 1

6, 2, 7, 3

6, 3, 6, 0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

In [Co(NH₃)₅CO₃]ClO₄, five ammonia ligands and one carbonate ligand is attached to the central cobalt atom. Hence, the coordination number is six.
Let X be the oxidation number of cobalt. X+(−2)+(−1)=0 or X=3. Hence, the oxidation number is 3.
The outer electronic configuration of cobalt (atomic number 27) is 3d⁷4s². The outer electronic configuration of Co⁺³ will be 3d⁶4s⁰. Thus it contains six d electrons.
[Co(NH₃)₅CO₃]ClO₄ is inner orbital or low spin complexes. all the electrons are paired due to d²sp³ hybridization of Co⁺³ ion. Hence, the number of unpaired d electrons is zero.