Consider the following complex [Co(NH₃)₅CO₃]ClO₄.The coordination number, oxidation number, number of d-electrons and number of unpaired d-electrons, respectively, on the metal are

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7, 1, 6, 4

7, 2, 7, 1

6, 2, 7, 3

6, 3, 6, 0

answer is A.

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Detailed Solution

In [Co(NH₃)₅CO₃]ClO₄, five ammonia ligands and one carbonate ligand is attached to the central cobalt atom. Hence, the coordination number is six.
Let X be the oxidation number of cobalt. X+(−2)+(−1)=0 or X=3. Hence, the oxidation number is 3.
The outer electronic configuration of cobalt (atomic number 27) is 3d⁷4s². The outer electronic configuration of Co⁺³ will be 3d⁶4s⁰. Thus it contains six d electrons.
[Co(NH₃)₅CO₃]ClO₄ is inner orbital or low spin complexes. all the electrons are paired due to d²sp³ hybridization of Co⁺³ ion. Hence, the number of unpaired d electrons is zero.