Consider the following complexes 

$$\begin{gathered} 1) {\mathrm{K}}_2{\mathrm{PtCl}}_{6 } 2) {\mathrm{PtCl}}_4.2{\mathrm{NH}}_3 \\ 3) {\mathrm{PtCl}}_4.3{\mathrm{NH}}_3 4) {\mathrm{PtCl}}_4.5{\mathrm{NH}}_3 \end{gathered}$$
Their electrical conductance in aqueous solutions are

coordination number of Pt is 6. Hence on aqueous solution the number of dissociated ions will be
I K₂[PtCl₆] − 3 ions
II [Pt(NH₃)₂Cl₄] − 0 ions
III [Pt(NH₃)₃Cl₃]Cl− 2 ions
IV [Pt(NH₃)₅Cl]Cl₃ − 4 ions
More is the number of ions, more is the electrical conductance.