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Q.

Consider the following complexes

 (P) Cr(CO)x      (Q)Cr(CO)(x1)PF3

If PF3 is better π accepter than CO, what will be the order of bond length of CO in complexes (P) and (Q).

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a

Q > P

b

P > Q

c

can not be compared

d

P = Q

answer is A.

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Detailed Solution

Due to the fact that PF3 is a greater "-acceptor" than CO, back bonding occurs in place of CO.So, CO B.L. gets shorter.

If PF3 is better π accepter than CO, what will be the order of bond length of CO in complexes (P) and (Q). then P > Q.

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