Consider the following compounds :
$(P) {ClF}_{3}$ $(Q) {BrF}_{3}$
The order of the angles between axial and equatorial bond pairs is :

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$P < Q$

$P = Q$

$\begin{aligned} P > Q \end{aligned}$

None of these

answer is A.

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Detailed Solution

The order of the angles between axial and equatorial bond pairs is Chlorine trifluoride >Bromine trifluoride compounds
Chlorine trifluoride has a trigonal bipyramidal molecular structure with a 175° $F - Cl - F$ bond angle.
The angle created by axial fluorine and equatorial fluorine is 86.2°.
As size of " C.A.个,B.A."↓
Thus, P > Q
Hence correct option is A.

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