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Q.

Consider the following compounds ${PH}_{5}, {SH}_{6}, {PH}_{4} I, {XeH}_{4}, {NH}_{4} Cl, H_{2} S$
Let x be the number of compounds which exist (stable) and y be the total number of identical bond angles in these stable compounds. Find the sum of x and y.

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answer is 15.

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Detailed Solution

The compounds which are stable from the given options are

${PH}_{4} I, {NH}_{4} Cl, H_{2} S$

So, $x = 3$

Now, the number of identical bond angle in these three species are 12. Thus,

Y=12

Thus, the sum of x and y,

$x + y = 3 + 12 = 15 .$

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Consider the following compounds PH5,SH6,PH4I,XeH4,NH4Cl,H2S Let x be the number of compounds which exist (stable) and y be the total number of identical bond angles in these stable compounds. Find the sum of x and y.