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Consider the following conversions:
$(i) O_{(g)} + e^{-} \to {O^{-}}_{(g)}, Δ H_{1}$ $(i i) F_{(g)} + e^{-} \to {F^{-}}_{(g)}, Δ H_{2}$
$(i i i) C l_{(g)} + e^{-} \to C {l^{-}}_{(g)}, Δ H_{3}$ $(i v) {O^{-}}_{(g)} + e^{-} \to {O^{2 -}}_{(g)}, Δ H_{4}$
That according to given information the incorrect statements is:

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$Δ H_{3}$ is more negative than $Δ H_{1}$ and $Δ H_{2}$

$Δ H_{1}$ is less negative than $Δ H_{2}$

$Δ H_{1}$ , $Δ H_{2}$ and $Δ H_{3}$ are negative whereas $Δ H_{4}$ is positive

$Δ H_{1}$ and $Δ H_{3}$ are negative whereas $Δ H_{2}$ and $Δ H_{4}$ are positive

answer is D.

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Detailed Solution

order of electron gain enthalpy Cl > F > O
Second electron gain enthalpy for an element is always positive.

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