Consider the following data for CaCl2: Conc.(mole/litre) 0.5 1λm(Ω−1cm2mole−1) 300 280If the value of λm0(Ω−1cm2mole−1) of CaCl2 is X then the value of X80 is (to the nearest integer) is ________

Equation of straight line (y−300)=280−3001−0.5(x−0.5) y−300=−40x+20 y=−40x+320Intercept ⇒320=λm0]

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Consider the following data for $C a C l_{2}$ :
$\begin{array}{l} C o n c . (m o l e / l i t r e) 0.5 1 \\ λ_{m} (Ω^{- 1} c m^{2} m o l e^{- 1}) 300 280 \end{array}$
If the value of $λ_{m}^{0} (Ω^{- 1} c m^{2} m o l e^{- 1})$ of $C a C l_{2}$ is X then the value of $\frac{X}{80}$ is (to the nearest integer) is ________

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answer is 4.

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Detailed Solution

Equation of straight line
$(y - 300) = \frac{280 - 300}{1 - 0.5} (x - 0.5) y - 300 = - 40 x + 20 y = - 40 x + 320$
Intercept
$\Rightarrow 320 = λ_{m}^{0}]$

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