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Q.

Consider the following E⁰ values
E⁰ Fe³⁺ / Fe²⁺ = + 0.77 V
E⁰Sn²⁺ / Sn = – 0.14 V

Under standard conditions the potential for the reaction
    $\large S{n_{\left( s \right)}}\, + \,2F{e^{3 + }}_{\left( {aq} \right)}\, \to \,2F{e^{2 + }}_{\left( {aq} \right)} + \,S{n^{2 + }}_{\left( {aq} \right)}$    is

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a

1.68 V

b

0.91 V

c

1.40 V

d

0.63 V

answer is C.

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Detailed Solution

From the given cell reaction anode is Sn and cathode is Fe.

${E_{cell}} = E_c^o - E_a^o$

= 0.77 - (-0.14) = 0.91 V

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Consider the following E0 values E0 Fe3+ / Fe2+ = + 0.77 V E0Sn2+ / Sn = – 0.14 V Under standard conditions the potential for the reaction is