Consider the following first order reversible reaction

R= Reactant P= Product
(Assume Arrhenius pre exponential factor for forward and backward reaction is same)
Rate constant $k_{1} = 4 \times 10^{- 2} s^{- 1}$
Select the correct option(s)

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The value of $k_{2} = 0.44 \times 10^{- 3} s^{- 1}$

Equilibrium constant for the reaction is 9

On increasing temperature of system, the percentage increase in rate constant of backward reaction is more than rate constant of forward reaction.

The reaction is exothermic in nature

answer is B, C, D.

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Detailed Solution

$\begin{array}{l} K = \frac{[P]}{[R]} = \frac{3.6}{0.4} = 9 \\ K = \frac{k_{1}}{k_{2}} \Rightarrow 9 = \frac{4 \times 10^{- 2}}{k_{2}}, k_{2} = \frac{4 \times 10^{- 2}}{9} \\ = 0.44 \times 10^{- 2} s^{- 1} \\ k_{1} > k_{2}, E_{a_{2}} > E_{a_{1}} \Rightarrow ΔH < 0 \end{array}$