Consider the following frequency distribution :

The upper limit of the median class is:

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17.5

18.5

answer is B.

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Detailed Solution

Given frequency table is,
Question Image

Consider the table,
Question Image

Here the given class can be made continuous by adding 0.5 to the upper limit and subtracting 0.5 from the lower limit from each class.
The formula to find the median class is.

n + 1 2 t h

Here, the sum of all the frequencies, n = 29 from the given table.
Therefore,

n + 1 2 t h = 29 + 1 2 i ℏ ⇒ n + 1 2 t h = 302 i / t ⇒ n + 1 2 t h = 15 t h

15 is the class where the median is lying.
And the 15th class lies in the interval 12.5-17.5.
Thus, the upper limit of the median class is 17.5.
Therefore, option 2 is correct.

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