Consider the following in unbalanced reaction and identify the correct statement(s)
 $P_4+NaOH+H_{2}O\to Na{H}_{2}P{O}_2+P{H}_3$

This is an example of disproportionation redox reaction

Equivalent weight of NaOH = molecular weight of NaOH 

Equivalent weight of $\left(P_4\right)=\frac{8[\text{atomic\hspace{0.17em}weight\hspace{0.17em}of\hspace{0.17em}P]}}{6}$

$Na{H}_{2}P{O}_2$ has two acidic H – atoms