Consider the following molecules :

$\begin{array}{l}{\mathrm{H}}_2\mathrm{O}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{H}}_2\mathrm{S}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{H}}_2\mathrm{Se}{\mathrm{H}}_2\mathrm{Te}\end{array}$

$\mathrm{I} \mathrm{II} \mathrm{Ill} \mathrm{IV}$

Arrange these molecules in Increasing order of bond angles

The molecules in Increasing order of bond angles are ${\mathrm{H}}_2\mathrm{O}>{\mathrm{H}}_2\mathrm{S}>{\mathrm{H}}_2\mathrm{Se}>{\mathrm{H}}_2\mathrm{Te}$i.e.$\mathrm{II} < \mathrm{IV} < \mathrm{III} < \mathrm{I}$

Due to bond pair and bond repulsion when bond pairs become closer to a certain atom, the bond angle increases as the electronegative of the core atom increases.