Consider the following pairs of electrons
A: $\text{a) }\mathrm{n}=3\ell =1m_{\ell }=-1m_s=+\frac{1}{2}$
$\text{b) }\mathrm{n}=3\ell =2m_{\ell }=1m_s=+\frac{1}{2}$
B.  $\text{a) }\mathrm{n}=3\ell =\mathbf{2}{m}_{\ell }=-2m_s=-\frac{1}{2}$
$\text{b) }\mathrm{n}=3\ell =2m_{\ell }=-1m_s=-\frac{1}{2}$
C. $\text{a) }\mathrm{n}=4\ell =2m_{\ell }=2m_s=+\frac{1}{2}$
$\text{b) }n=3\ell =2m_{\ell }=2m_s=+\frac{1}{2}$
The pair of electron present in degenerate orbitals is/are