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Q.

Consider the following processes
                                 ΔH(kJ/mol)
12AB                + 150
3B2C+D      - 125
E+A2D         + 350
For B+DE+2C,  ΔH will be

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a

525 kJ / mol

b

325 kJ / mol

c

– 325 kJ / mol

d

– 175 kJ / mol

answer is B.

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Detailed Solution

Adding all the equations, we get
                                             ΔH
A2B                                300kJ/mol
3B2C+D                 125kJ/mol
2DA+E                350kJ/mol
B+DE+2C;ΔH=(300125350)¯=175kJ/mol

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