Consider the following radioactive decay process
$_{84}^{218} A \overset{a}{⟶} A_{1} \overset{5}{⟶} A_{2} \overset{γ}{⟶} A_{3} \overset{a}{⟶} A_{4} \overset{β^{+}}{⟶} A_{5} \overset{γ}{⟶} A_{6}$
The mass number and the atomic number $A_{6}$ are given by :

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210 and 80

211 and 80

210 and 82

210 and 84

answer is C.

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Detailed Solution

$_{84}^{218} A {\overset{α}{⟶}}_{82}^{214} A_{1} {\overset{β^{-}}{⟶}}_{83}^{214} A_{2} {\overset{γ}{⟶}}_{83}^{214} A_{3}$

$_{83}^{214} A_{3} {\overset{α}{⟶}}_{81}^{210} A_{4} {\overset{β^{+}}{⟶}}_{80}^{210} A_{5} {\overset{γ}{⟶}}_{80}^{210} A_{6}$

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