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Q.

Consider the following radioactive decay process 
 84218AααA1β-A2γA3αA4β+A5γA6
The mass number and the atomic number of A6 are given by:

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a

211 and 80

b

210 and 80

c

210 and 82

d

210 and 84

answer is B.

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Detailed Solution

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Effectively change in A and Z is due to α - only for the given Reaction.
A1 = 218 - 2 x 4 = 210
Z1 = 84 - 2 x 2 = 80

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