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Q.

Consider the following reaction:
 3PbCl2+2(NH4)3PO4Pb3(PO4)2+6NH4Cl
If 72 millimoles of  PbCl2 is mixed with 50 millimoles of  (NH4)3PO4, then  the  amount Pb3(PO4)2 of formed is ___________ millimoles (nearest integer)
 

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answer is 24.

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Detailed Solution

 3PbCl2+2(NH4)3PO4Pb3(PO4)2+6NH4Cl
3m mole   2m mole   1m mole  72m mole  50m mole   ?
  (48m  molerequired)
Limiting Reagent is (NH4)3PO4
2m  mol  of(NH4)3PO41m  mol  of  Pb3(PO4)2 2m  mole  of  (NH4)3PO41m  mol  of  Pb3(PO4)2  48m  mol  of  (NH4)3PO4?
No.of m mole of Pb3(PO4)2=48×12
 =24m  mole  of    Pb3(PO4)2
 

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