Q.

Consider the following reaction approaching equilibrium at 27°C and 1 atm pressure
A+Bkr=102kj=102C+D
The standard Gibb’s energy change Δ,G0 at 27°C is (-) _________kJ-1
(Nearest integer)
(Given: R=8.3JK1moI1 and In 10=2.3)
 

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answer is 6.

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Detailed Solution

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A+Bkr=102kj=103C+D
k2 = 10
Δ10=2.303RT by k=8.3×103×300×2.3=5.72=6kg

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