Consider the following reaction:
$N_{2} O_{4} ⇌ 2 {NO}_{2} (g); {ΔH}^{o} = 58 KJ$
For each of the following cases (a, b), the direction in which the equilibrium shifts is :
(a)Temperature is decreased
(b)pressure is increased by adding N₂ at constant T.

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(a) towards product, (b) towards reactant

(a) towards reactant, (b) towards product

(a)towards reactant, (b) no change

(a)towards product, (b) no change

answer is A.

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Detailed Solution

According to Le-chatelier’s principle,
(i) For endothermic reaction, decrease in temperature,
Equilibrium shift in the reactant side.
(ii) By adding inert gas at same temperature, on increase in
Pressure, no shifting occurs.

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