Consider the following reactions (unbalanced) Zn + hot conc. H2SO4→G+R+XZn+conc.NaOH→T+QG+H2S+NH4OH→Z(a precipitate)+X+Y Choose the correct option(s)

Zn+H2SO4+→G+R+X Hot&ConcZn+H2SO4→ZnSO4+SO2+2H2O G R XZn+Conc.NaOH→Na2ZnO2+H2 T QZnSO4+H2S+NH4OH→ZnS+NH42SO4+H2O G Z Y X(a) Oxidation state of Zn in Na2ZnO2 is + 2(b) Bond order of Q is one for H2(c) ZnS is white in colour(d) SO2 is angular in shape

Consider the following reactions (unbalanced) Zn + hot conc. H2SO4→G+R+XZn+conc.NaOH→T+QG+H2S+NH4OH→Z(a precipitate)+X+Y Choose the correct option(s)

Zn+H2SO4+→G+R+X Hot&ConcZn+H2SO4→ZnSO4+SO2+2H2O G R XZn+Conc.NaOH→Na2ZnO2+H2 T QZnSO4+H2S+NH4OH→ZnS+NH42SO4+H2O G Z Y X(a) Oxidation state of Zn in Na2ZnO2 is + 2(b) Bond order of Q is one for H2(c) ZnS is white in colour(d) SO2 is angular in shape

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Consider the following reactions (unbalanced)
Zn + hot conc. $H_{2} S O_{4} \to G + R + X$
$Z n + c o n c . N a O H \to T + Q$
$G + H_{2} S + N H_{4} O H \to Z (a p r e c i p i t a t e) + X + Y$
Choose the correct option(s)

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The oxidation state of Zn in T is + 1

Bond order of Q is 1 in its ground state

Z is dirty white in color

R is a V – shaped molecule

answer is A, C, D.

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Detailed Solution

$\begin{array}{l} Z n + H_{2} S O_{4} + \to G + R + X \\ H o t & C o n c \\ Z n + H_{2} S O_{4} \to Z n S O_{4} + S O_{2} + 2 H_{2} O \\ (G) (R) (X) \\ Z n + C o n c . N a O H \to N a_{2} Z n O_{2} + H_{2} \\ (T) (Q) \\ Z n S O_{4} + H_{2} S + N H_{4} O H \to Z n S + {(N H_{4})}_{2} S O_{4} + H_{2} O \\ (G) (Z) (Y) (X) \end{array}$
(a) Oxidation state of Zn in Na₂ZnO₂is + 2
(b) Bond order of Q is one for H₂
(c) ZnS is white in colour
(d) SO2 is angular in shape