Consider the following reactions:
(i) ${\mathrm{PCl}}_3+3{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{H}}_3{\mathrm{PO}}_3+3\mathrm{HCl}$
(ii) ${\mathrm{SF}}_4+3{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{H}}_2{\mathrm{SO}}_3+4\mathrm{HF}$
(iii) ${\mathrm{BCl}}_3+3{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{H}}_3{\mathrm{BO}}_3+3\mathrm{HCl}$
(iv) ${\mathrm{XeF}}_6+3{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{XeO}}_3+6\mathrm{HF}$
Then according to given information the incorrect statement is:

During the (i) reaction the hybridization of 15th group element does not change

During the (iv) reaction the hybridization of 18th group element does not change

During the (iii) reaction the hybridization of 13th group element does not change

During the (ii) reaction the hybridization of 16th group element has been changed