Consider the following reactionsK2Cr2O7→−H2O KOH [A]→−H2O H2SO4 [B]+K2SO4The products [A] and [B], respectively are :

K2Cr2O7→−H2O KOH K2CrO4→−H2O H2SO4 K2Cr2O7+K2SO4 [A] [B]

K2Cr2O7→−H2O KOH K2CrO4→−H2O H2SO4 K2Cr2O7+K2SO4 [A] [B]

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Consider the following reactions
$K_{2} {Cr}_{2} O_{7} \to_{- H_{2} O}^{KOH} [A] \to_{- H_{2} O}^{H_{2} {SO}_{4}} [B] + K_{2} {SO}_{4}$
The products [A] and [B], respectively are :

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$K_{2} {CrO}_{4} and K_{2} {Cr}_{2} O_{7}$

$K_{2} {CrO}_{4} and {Cr}_{2} O_{3}$

$K_{2} Cr (OH)_{6} and {Cr}_{2} O_{3}$

$K_{2} {CrO}_{4} and CrO$

answer is C.

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$K_{2} {Cr}_{2} O_{7} \to_{- H_{2} O}^{KOH} K_{2} {CrO}_{4} \to_{- H_{2} O}^{H_{2} {SO}_{4}} K_{2} {Cr}_{2} O_{7} + K_{2} {SO}_{4} [A] [B]$

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