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Consider the following reaction
Which of the following base will give best yield of the alkene II as the major product?

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${(C_{2} H_{5})}_{3} {CO}^{-}$

$C_{2} H_{5} O^{-}$

${CH}_{3} O^{-}$

${({CH}_{3})}_{3} {CO}^{-}$

answer is D.

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Detailed Solution

Alkene treated with potassium tertiary butoxide instead of Ethoxide Hoffmann product formed.Bulkier the base, stearic course will play the key role.

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