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Q.

Consider the following redox reaction in which compound 'X' is a product.
P4 + H2O + KOH → PH3 + X.
The oxidation state of phorsphorous in compound 'X' is

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a

+ 1

b

+ 3

c

+ 4

d

+ 5

answer is A.

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Detailed Solution

P4 + H2O + KOH → PH3 + X.
'X' is KH2PO2
KH2PO2
(+1) + 2(+1) + X + 2(-2) = 0
X = +1
Oxidation state 'P' in KH2PO2 = +1

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