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Q.

Consider the following reduction process

Zn2++2eZns,      Eo=0.76V

Ca2++2eCas,     Eo=2.87V

Mg2++2eMgs,     Eo=2.36V

Ni2++2eNis,     Eo=0.25VThe reducing power of the metals increases in the order        

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a

Ni<Zn<Mg<Ca

b

Zn<Mg<Ni<Ca

c

Ca<Zn<Mg<Ni

d

Ca<Mg<Zn<Ni

answer is B.

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Detailed Solution

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Higher the oxidation potential, higher will be the reducing power. So, the order of reducing behavior is Ca>Mg>Zn>Ni

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