Consider the following staements
Statement 1: ${[C r {(N H_{3})}_{6}]}^{3 +}$ is an inner orbital complex with crystal field stabilization energy equal to $- 1.2 Δ_{0}$
Statement 2: The octahedral complex formed by joining the $C N^{-}$ ligands to $F e^{3 +}$ ion has theoretical value of spin only magnetic moment equal to 1.73 BM
Statement 3: $N a_{2} S + N a_{2} [F e {(C N)}_{5} N O] \to N a_{4} [F e {(C N)}_{5} N O S],$ In reactant and product the oxidation states of iron are same and arrange in the order of true / false

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FTF

TTF

TTT

FFF

answer is C.

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Detailed Solution

${[C r {(N H_{3})}_{6}]}^{3 +} \Rightarrow d^{3}, t_{2 g}^{1, 1, 1} e g^{0, 0}$

$C F S E = - 0.4 \times 3 Δ_{0} = - 1.2 Δ_{0}$

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