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Consider the following statements.

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$C H_{3} - C H_{2} - C H_{2} - I$ will react more readily than ${(C H_{3})}_{2} C H I$ for $S_{N^{2}}$

${CH}_{3} - {CH}_{2} - {CH}_{2} - Cl$ will react more readily than $C H_{3} - C H_{2} - C H_{2} - B r$ for $S_{N^{2}}$ reaction.

$C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r$ will react more readily than ${(C H_{3})}_{3} C - C H_{2} - B r$ for $S_{N^{2}}$ reactions.

$C H_{3} - O - C_{6} H_{5} - B r$ will react more readily than $N O_{2} - C_{6} H_{5} - C H_{2} B r$ for $S_{N^{2}}$ reaction.

answer is A, C.

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Detailed Solution

Order .of $R - X$ of Reaction $1^{0} > 2^{0} > 3^{0}$
2) $R - F < R - C l < R - R r < R - I$
3) $S N^{2} \propto \frac{1}{l e s s}$ stem calls Hinderence.

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