Consider the following statements :

${\mathbf{S}}_1:{\mathrm{N}}_2{\mathrm{H}}_4$ is pyramidal about each N atom.

${\mathrm{S}}_2:{\mathrm{NH}}_2\mathrm{OH}$ is pyramidal about the N atom and bent about the O atom.

${\mathbf{S}}_3:{\mathrm{CH}}_3\mathrm{COOH}$ is trigonal about the carbon atom (attached to O and ${\mathrm{CH}}_3$) and out of these select the correct one.

${\mathbf{S}}_1:{\mathrm{N}}_2{\mathrm{H}}_4$ is pyramidal about each N atom because A pyramidal organizational structure is one in which the controlling shareholder at the top of the pyramid indirectly controls a corporation through layers of intermediary entities.

${\mathrm{S}}_2:{\mathrm{NH}}_2\mathrm{OH}$ is pyramidal about the N atom and bent about the O atom because Due to the fact that the central nitrogen atom has 4 electron pairs around it (three bond pairs plus one lone pair), which makes it an ${\mathrm{AX}}_3\mathrm{N}$ type molecule, the molecular geometry of ${\mathrm{NH}}_2\mathrm{OH}$ is trigonal pyramidal, and its electron geometry is tetrahedral.

${\mathbf{S}}_3:{\mathrm{CH}}_3\mathrm{COOH}$ is trigonal about the carbon atom because Carbon 2 is only attached to the three atoms, and it does also not contain any lone pair of electrons, hence, as per VSEPR theory, this atom holds the electron and molecular geometry of trigonal planar.

Hence, the option D is correct.