Consider the following statements : 

Statement-1 : Generally, square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess plane of symmetry.

Statement-2 :  ${\mathrm{\Delta }}_t=\frac{4}{9}{\mathrm{\Delta }}_0$

Statement-3: In octahedral complexes each electron entering the $t_{2g}$ orbitals stabilizes the complex ion by $0.4 {\mathrm{\Delta }}_0$ and each electron entering the $e_g$ orbital destabilizes the complex by an amount of $0.6 {\mathrm{\Delta }}_0$ • 

Select the correct statement from the codes given below.

Square planar complexes holds plane of symmetry. Thus, this complexes doesn’t show optical isomerism.

in the tetrahedral field crystal field splitting is 4/9th of the crystal field splitting in octahedral field.

Energy level of unsplitted d orbitals and $t_{2g}$​ orbitals difference $=0.4 {\mathrm{\Delta }}_0$

The energy level of the unsplitted orbitals and eg level difference $=0.6 {\mathrm{\Delta }}_0$.

Thus, in octahedral complexes, all the electron entering the $t_{2g}$​ orbitals balance the complex ion by $0.4 {\mathrm{\Delta }}_0$​, and every electron entering the, $e_g$ orbital destabilizes the complex by an amount of $0.6 {\mathrm{\Delta }}_0$​.

Hence, options B and C are correct.