Consider the following statements.
I) ${Li}_{2}$ in vapour state is paramagnetic.
II) $C_{2}$ in vapour state is diamagnetic.
III) ${Be}_{2}$ does not exist.
IV) Triple bond in $N_{2}$ consists of only pi bonds.
Among these statements

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II and IV are incorrect

All are incorrect

I and III are correct

I and IV are incorrect

answer is C.

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Detailed Solution

${Li}_{2}$ in vapour state is diamagnetic;

${Li}_{2} - KK {(σ_{2 s})}^{2}; B . O = \frac{4 - 2}{2} = 1$

Triple bond in $N_{2}$ consists of one sigma and two pi bonds;

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