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Q.

Consider the following system of equations
αx+2y+z=12αx+3y+z=13x+αy+2z=β
For some α,β. Then which of the following is NOT correct.

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a

It has no solution if α=1 and β2

b

It has a solution for all,α1 and β=2

c

It has no solution for α=3 and for all β2

d

It has no solution for  α=1 and for all β

answer is D.

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Detailed Solution

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Δ=α212α313α2=α(6α)2(4α3)+12α29=α22α3=(α3)(α+1)Δ1=121131βα2=1(6α)2(2β)+1(α3β)=2βΔ2=α112α113β2=α(2β)2α(2β)+3(0)=2α+αβ=α(2+β)Δ3=α212α313αβ=α(3βα)2(2αβ3)+12α29=α2αβ3α=1,β2Δ=0,Δ10 no solution α1,β=2Δ0 unique solution α=3,β2Δ=0,Δ10 no solution α=1,β no solution or infinitely many sol. 

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