Consider the following table
Gas a (kPa dm⁶ mol^-1) b (dm³ mol^-1)
A 642.32 0.05196
B 155.21 0.04136
C 431.91 0.05196
D 155.21 0.4382

a and b are van der waals constants. The correct statement about the gases is

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Gas C will occupy lesser volume then gas A:gas B will be lesser Compressible than gas D

Gas C will occupy more volume than gas A: gas B will be more compressible than gas D

Gas C will occupy more volume than gas A: gas B will be lesser compressible than gas D

Gas C will occupy lesser volume than gas A:gas B will be more compressible than gas D

answer is C.

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Detailed Solution

Gases A and C have the same value of 'b', but different values of 'a', so the gas with the higher value has more attractive force, closer molecules, and less volume. increase. Gases B and D have the same value of 'a' but different values of 'b', so the gas with the lower value is more compressible.

Therefore the required option is C

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