Consider the following table
Gas $a / (k P a d m^{6} {mol}^{- 1})$ $b / (d m^{3} m o l^{1})$
A 642.32 0.05196
B 155.21 0.04136
C 431.91 0.05196
D 155.21 0.4382
a and b are vander waals constant. The correct statement about the gases is

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Gas C will occupy lesser volume than gas A; gas B will be lesser compressible than gas D

Gas C will occupy more volume than gas A: gas B will be lesser compressible than gas D

Gas C will occupy more volume than gas A; gas B will be more compressible than gas D

Gas C will occupy lesser volume than gas A; gas B will be more compressible than gas D

answer is C.

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Detailed Solution

Gas A and C have same value of ;b' but different value of 'a' so gas having higher value of ;a' have more force of attraction so molecules will be more closer hence occupy less volume. Gas B and D have same value of 'a' but different value of 'b' so gas having lesser value of 'b' will be more compressible

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