Q.

Consider the following three compounds 
(i)AX2nn     (ii)AX3n    (iii)AX4nn+ , where central atom A is 15th group element and their maximum covalency is  3n.  If total number of protons in surrounding atom  X is n.  and value of  n  is one, then calculate value of  "x3+y2+z". (Where  x,y and z  are total number of lone pairs at central atom in compound  (i),(ii)  &  (iii) respectively.

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answer is 9.

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Detailed Solution

n=1,  then  X=H; A=N
(i)NH2    (ii)NH3   (iii)NH4+ 
Lone pair  x=2,y=1,z=0
 x3+y2+x=(2)3+(1)2+(0)=9

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