Consider the following two reactions :
${Cd}^{2 +} (aq .) + 2 H_{2} {NCH}_{2} {CH}_{2} {NH}_{2} \overset{K_{1}}{⟶} A$
${Cd}^{2 +} (aq.) + 2 {CH}_{3} CH ({NH}_{2}) CH ({NH}_{2}) {CH}_{3} \overset{K_{2}}{⟶} B$
According to given information the correct statement is are :

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A is optically active while B is optically inactive

both are optically inactive

both are optically active

A is optically inactive while B is optically active.

answer is B.

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Detailed Solution

${Cd}^{2 +} (aq .) + 2 en \overset{K_{1}}{⟶} \underset{Optically active ligand}{{[Cd (en)_{2}]}^{2 +}}$
${Cd}^{2 +} (aq .) + 2 bn \overset{K_{2}}{⟶} \underset{Optically active ligand}{{[Cd (bn)_{2}]}^{2 +}}$

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