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Consider the frequency distribution:

Class
0-10
10-20
20-30
30-40
40-50
Frequency
7
10
15
8
10

The sum of the lower limit of the modal class and the upper limit of the median class is

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answer is B.

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Detailed Solution

The given frequency distribution table is:

Class	0-10	10-20	20-30	30-40	40-50
Frequency	7	10	15	8	10

The modal class is defined as the class interval having the highest frequency.
Here, the highest frequency is 15.
Then, the modal class is

20 − 30

and its lower limit is

20

.
The cumulative frequency distribution will be:

Class	Frequency	Cumulative Frequency
0-10	7	7
10-20	10	7+10=17
20-30	15	17+15=32
30-40	8	32+8=40
40-50	10	40+10=50

Here,

N = 50 ⇒ N 2 = 502 = 25

The cumulative frequency just more than 25 is 32 and its class is

20 − 30

, whose upper limit is 30.
So, the sum of the lower limit of the modal class and the upper limit of the median class is,
20 + 30 = 50.
Therefore, the required sum is 50.
Thus, the correct answer is option 2.

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