Consider the given reaction and identify incorrect statement from the given following

 

$\mathbf{B}\stackrel{\mathbf{Na}\mathbf{/}{\mathbf{NH}}_3}{\leftarrow }{\mathbf{CH}}_3\mathbf{-}\mathbf{C}\equiv \mathbf{C}\mathbf{-}\mathbf{C}{\mathbf{H}}_3\underset{\Delta }{\overset{\mathbf{Pd}\mathbf{/}\mathbf{C}}{\to }}\mathbf{A}$

A) A is more soluble than B.

B) The boiling point of A is higher than that of B & melting point of A is lower than that of B  

C) A is more polar than B because dipole moment of A is zero.

 D) catalytic hydrogenation of A and B gives different hydrocarbons

Identify the incorrect statements from the options given below