Consider the given reaction:
$B (OH)_{3} + NaOH ⇌ Na [B (OH)_{4}]$
How can this reaction is made to proceed in forward direction?

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Addition of cis 1, 2 diol

Addition of borax

Addition of trans 1, 2 diol

Addition of Na₂HPO₄

answer is A.

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Detailed Solution

B(OH)₃ is a weak acid while NaOH is a strong base. Any additional compound that enhances the acidity of B(OH)₃, increases the rate of reaction. Among the given options, acidity is either increases by cis-1,2-diol or trans-1,2-diol.

In cis-1,2-diol, two -OH groups present on the same side and forms chelated complex with B(OH)₃. This enhances the stability and acidity of B(OH)₃ which results in increasing the rate of reaction.

In trans-1,2-diol, two -OH groups present on the opposite sides. As a result, chelated complex cannot formed between trans-1,2-diol and B(OH)₃.

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