Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers, l = 1 and 2 are, respectively

The electronic configuration of ${ }_{24}\mathrm{Cr}$ is $\left(1s{)}^2\right(2s{)}^2\left(2p{)}^6\right(3s{)}^2\left(3p{)}^6\right(3d{)}^5(4s{)}^1$

$l=1$ corresponds top orbital. The number of electrons in p orbitals is 6 + 6 = 12

$l=2$ corresponds to d orbital. The number of electrons in d orbitals is 5