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Consider the half reaction, ${Cr}_{2} O_{7}^{2 -} \overset{H^{+}}{\to} {Cr}^{3 +}$ , the number of H⁺ ions and electrons involved in the balanced half reaction are respectively

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14 , 6

14 , 3

8 , 6

12 , 3

answer is A.

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Detailed Solution

${Cr}_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 {Cr}^{3 +} + 7 H_{2} O$

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