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Q.

Consider the integrals I1=e1excos2xdx,I2=01ex2cos2xdx,I3=01ex22cos2xdx,I4=01ex22dx
Then
 

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a

I2>I4>I1>I3

b

I2<I4<I1>I3

c

I1<I2<I3<I4

d

I1>I2>I3>I4

answer is C.

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Detailed Solution

Since 0<x<1x>x2>x22x<x2<x22ex<ex2<ex22

excos2x<excos2x<ex22cos2x<ex2/2

01excos2xdx<01ex2cos2xdx<01ex22cos2xdx<01ex22dx

I1<I2<I3<I4

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