Consider the lines $\frac{x-2}{3}=\frac{y+1}{-2},z=2$ and $\frac{x-1}{1}=\frac{2y+3}{3}=\frac{z+5}{2}$ is 

The given values all the choices are easily verified

$\frac{x-2}{3}=\frac{y+1}{-2}=\frac{z-2}{0}......\left(1\right)$

and $\frac{x-1}{1}=\frac{y+\frac{3}{2}}{\frac{3}{2}}=\frac{z+5}{2}......\left(2\right)$

Direction numbers of the two lines are respectively  $(3,-2,0)\text{ and }\left(1,\frac{3}{2},2\right)$

Since $3\times 1+(-2)\times \frac{3}{2}+2\times 0=0,$ the given lines are at right angles.