Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Consider the meter bridge circuit without neglecting end corrections. If we used 100Ω and 200Ω resistance in place of R and S respectively, we get null deflection at l1=33.0 cm. If we interchange the resistances, the null deflection was found to be at l2=67.0 cm. If α and β are the end correction, then the value of α+β should be

Question Image

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

α=R2l1R1R2=(200)(33)(100)(67)100200=1cm,  β=R1l1R2l2R1R2100=(33)(100)(200)(67)100200100=1cm

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Consider the meter bridge circuit without neglecting end corrections. If we used 100Ω and 200Ω resistance in place of R and S respectively, we get null deflection at l1=33.0 cm. If we interchange the resistances, the null deflection was found to be at l2=67.0 cm. If α and β are the end correction, then the value of α+β should be