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Consider the molecules ${CH}_{4}, {NH}_{3} and H_{2} O .$ Which of the given statements is false?

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$The H - C - H bond angle in {CH}_{4}, the H - N - H bond angle in {NH}_{3}, and the H - O - H bond angle in H_{2} O are all greater than 90^{\circ}$

$The H - O - H bond angle in H_{2} O is larger than the H - C - H bond angle in {CH}_{4} .$

$The H - O - H bond angle in H_{2} O is smaller than the H - N - H bond angle in {NH}_{3} .$

$The H - C - H bond angle in {CH}_{4} is larger than the H - N - H bond angle in {NH}_{3} .$

answer is B.

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Detailed Solution

Note: The geometry of H₂O should have been tetrahedral if there are all bond pairs. But due to presence of two lone pairs the shape is distorted tetrahedral. Hence bond angle reduced to 104.5° from 109.5°.

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