Q.

Consider the motion of a positive point charge in a region where there are simultaneous uniform electric and magnetic fields  E=E0j^  and   B=B0j^. At time t =0, this charge has velocity υ in the in the x-y plane, making an angle θ with the x-axis. Which of the following option(s) is (are) correct for time t > 0 ?

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a

If  θ=90o the charge undergoes linear but accelerated motion along the y-axis

b

If  θ=0o, the charge undergoes helical motion with constant pitch along the y-axis.

c

If θ=0o, the charge moves in a circular path in the x-z plane.

d

If θ=10o, the charge undergoes helical motion with its pitch increasing with time, along the y-axis.

answer is C, D.

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Detailed Solution

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If θ=0o, the charged particle is projected along x- axis, due to magnetic field, B the charged particle will tend to move in a circular path in y-z plane but due to force of electric field E, the particle will move in a helical path with increasing pitch. Hence options (A) and (B) are wrong. If  θ=10o, we can resolve velocity into two rectangular components. One along x-axis

Question Image

(v cos 10°) and one along y- axis (v sin 10°). Due to v cos 10°, the particle will move in circular path and due to v sin 10° plus the force due to electric field, the particle will undergo helical motion with its pitch increasing. If θ = 90°, the charge is moving along the magnetic field. Therefore the force due to magnetic field is zero. But the force due to electric field will accelerate the particle along y-axis.

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