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Q.

Consider the parabola y2+2x+2y3=0 and match the items of List – I with those of the List-II 

 List – I List – II
A)2x5=0I)Vertex
B)32,1II)Focus
C)y+1=0III)Equation of directrix
D)(2,1)IV)Equation of axis
  V)Equation of latus rectum

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a

A – III, B – II, C – IV, D – I

b

A – V, B – I, C – IV, D – II

c

A – III, B – II, C – V, D – I

d

A – IV, B – I, C – III, D – II

answer is A.

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Detailed Solution

y2+2x+2y3=0

y2+2y=2x+3

y2+2y+1=2x+4

y+12=2x2 1

(1) Is in the form of
yk2=4axh4a=2a=12 
Where vertex A=h,k=2,1  
Focus S=ha,k=212,1=32,1
Directrix xh=a 
x2=122x5=0 
Equation of axis 
y+1=0

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