Consider the planes $3 x - 6 y + 2 z + 5 = 0 and 4 x - 12 y + 3 z - 3 = 0 .$ The plane, $67 x - 162 y + 47 z + 44 = 0$ bisect angle between given planes which

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Contains origin

is acute

right angle

is obtuse

answer is A, B.

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Detailed Solution

Bisects are $\frac{3 x - 6 y + 2 z + 5}{7} = \pm \frac{- 4 x + 12 y - 3 z + 3}{13}$
Contains origin means ‘+’ symbol
Functions 3 (-4) + (-6) (12) + 2 (-3) < 0

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